Asked by Maria

A car accelerates from rest at 1.70 m/s2 along a 220-m stretch of road. Find the car’s velocity at the end of the stretch.
Answered by Henry
d = 0.5at^2,
220 = 0.5 * 1.7 * t^2,
220 = 0.85t^2,
t^2 = 220 / 0.85 = 258.8,
t = sqrt(258.8) = 16.1 m.

V = at,
= 1.7 * 16.1 = 27.3 m/s.

Answered by Henry
CORRECTION:t = sqrt(258.8) = 16.1 s.
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