Ask a New Question

Question

A car accelerates from rest at 1.70 m/s2 along a 220-m stretch of road. Find the car’s velocity at the end of the stretch.
14 years ago

Answers

Henry
d = 0.5at^2,
220 = 0.5 * 1.7 * t^2,
220 = 0.85t^2,
t^2 = 220 / 0.85 = 258.8,
t = sqrt(258.8) = 16.1 m.

V = at,
= 1.7 * 16.1 = 27.3 m/s.

14 years ago
Henry
CORRECTION:t = sqrt(258.8) = 16.1 s.
14 years ago

Related Questions

a car accelerates from rest at a constant rate 'a' for some time. after which it decelerates at a co... A car accelerates from rest at a constant rate of 2.2 m/s2 for 6.9 s. How far does the car travel in... if a car accelerates from rest at a constant 5.5 m/s^2, how long will it take for the car to reach a... A car accelerates from rest at the rate of 1.4 + 3 (root)t mph per second for 4 seconds. How far do... A bus accelerates from rest at 1.5m/s^2 for 12s. It then travels for 25s after which it slows to a... A car accelerates from rest at 2.0 m/s2 for 20 s. The speed then remains constant for 20 s, after w... A car accelerates from rest at -2.10 m/s2. a. What is the velocity at the end of 4.0 s? b. What is... a car accelerates from rest to 28 m/s in 6 seconds. if the cars mass is 150.00 kg. what force is pr... A car accelerates from rest to a speed of 20 meters per second in 5 seconds. What is the car’s accel...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use