Ask a New Question

Question

A car accelerates from rest at a steady rate of 1 ms-2. Calculate:
(a) the time taken to reach 15 ms-1
(b) the distance travelled during this time
(c) the velocity of the car when it was 100 m from the start point
13 years ago

Answers

Henry
a. V = at = 15 m/s.
1*t = 15,
t = 15 s.

b. d = 0.5a*t^2,
d = 0.5*(15)^2 = 112.5 m.

c. V^2 = Vo^2 + 2a*d,
V^2 = 0 + 2*100 = 200,
V = 14.14 m/s.
13 years ago

Related Questions

A car accelerates from rest at 1.70 m/s2 along a 220-m stretch of road. Find the car’s velocity at t... A car accelerates from rest at 7.9 m/s2. How much time does it need to attain a speed of 5 m/s? A car accelerates from rest to 30m/s in 10s. What is the car's acceleration? a car accelerates from rest at a constant rate 'a' for some time. after which it decelerates at a co... a c accelerates from rest in a straight line. after 12 seconds, it's velocity is measured as 42 m/s.... A car accelerates from rest at the rate of 1.4 + 3 (root)t mph per second for 4 seconds. How far do... A bus accelerates from rest at 1.5m/s^2 for 12s. It then travels for 25s after which it slows to a... a car accelerates from rest to 28 m/s in 6 seconds. if the cars mass is 150.00 kg. what force is pr... A car accelerates from rest to a speed of 20 meters per second in 5 seconds. What is the car’s accel...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use