Question

if the diagonals of quadrilateral ABCD intersect at their midpoints, then the quadrilateral is a parallelogram.
Prove that AM MC
--- = ---
MB MD

Ive tried figuring out this question for a while now and I cant figure it out.

Answer 1

*******Prove that AM/BM = MC/MD

Answer 2

If AC and BD intersect at their mid-points, AM=MC, and BM=MD.
Therefore
AM/MC=BM/MD=1
Transpose to get:
AM/BM=MC/MD