Asked by kabelo

find the ratio of the intensities of two sounds if one is 8 dB louder than the other
Answered by drwls
10 dB would be a factor of 10 in intensity (power/area).

8 = 10 log_10(I2/I1)
I2/I1 = 10^0.8 = 6.31
Answered by MAZ-31
20 log (A1/A2) = 2

log(A1/A2) = 0.1

A1/A2 = 10^(0.1) = 1.2589
Answered by Ahmed
The ratio of the intensities of the two sound sources is: 𝐼_2/𝐼_1 = 2.

What is the difference in the intensity levels of these sounds?
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