Asked by Sandu
                Find the ratio of the pH of solution (I) containing 1 mol of CH3COONa and 1 mol of HCl in 1L and solution (II)
containing 1 mol of CH3COONa and 1 mol of CH3COOH in 1L
            
        containing 1 mol of CH3COONa and 1 mol of CH3COOH in 1L
Answers
                    Answered by
            DrBob222
            
    In equal quantities like this I would write it as
NaAc + HCl ==> HAc + NaCl
So you essentially have a solution of HAc (now not 1M but 0.5M) and you calculate the pH of that solution. Do the same for solution II using the HH equation, then find the ratio of the pH o the two solutions.
    
NaAc + HCl ==> HAc + NaCl
So you essentially have a solution of HAc (now not 1M but 0.5M) and you calculate the pH of that solution. Do the same for solution II using the HH equation, then find the ratio of the pH o the two solutions.
                    Answered by
            Sandu
            
    How the concentration of HAc in first solution became 0.5M
Can you explain pls
    
Can you explain pls
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.