Asked by jordyn
y=3⋅2^x
Find the equation of the line tangent to the graph of y at x=1.5.
Find the equation of the line tangent to the graph of y at x=1.5.
Answers
Answered by
bobpursley
ln y= ln3 + xln2
1/y y'=ln2
y'=2*2^x ln2
so that is the slope of the line
y=slope*x+b
1.5,3*2^1.5 is a point on the line, put those in for x and y, and solve for b.
1/y y'=ln2
y'=2*2^x ln2
so that is the slope of the line
y=slope*x+b
1.5,3*2^1.5 is a point on the line, put those in for x and y, and solve for b.
Answered by
jordyn
hmm... that's what i did but the internet math program says it's wrong. thanks though!
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