Vertical speed initial: -Vsin37
hf=hi+Vi*t-4.9t^2
0=380-Vsin37*t-4.9t^2 t is given at 4 seconds, solve for V.
horizontal distance:Vcos37*t
A plane dives at 37° to the horizontal and releases a package at an altitude of 380m. If the load is in the air for 4s, find:
a) the speed of the plane when it released the package;
b) the horizontal distance traveled by the package after it is released.
1 answer
1 answer