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A plane dives at 37° to the horizontal and releases a package at an altitude of 380m. If the load is in the air for 4s, find:

a) the speed of the plane when it released the package;


b) the horizontal distance traveled by the package after it is released.

14 years ago

Answers

bobpursley
Vertical speed initial: -Vsin37

hf=hi+Vi*t-4.9t^2
0=380-Vsin37*t-4.9t^2 t is given at 4 seconds, solve for V.

horizontal distance:Vcos37*t
14 years ago

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