Asked by applebottom
A plane dives at 37° to the horizontal and releases a package at an altitude of 380m. If the load is in the air for 4s, find:
a) the speed of the plane when it released the package;
b) the horizontal distance traveled by the package after it is released.
a) the speed of the plane when it released the package;
b) the horizontal distance traveled by the package after it is released.
Answers
Answered by
bobpursley
Vertical speed initial: -Vsin37
hf=hi+Vi*t-4.9t^2
0=380-Vsin37*t-4.9t^2 t is given at 4 seconds, solve for V.
horizontal distance:Vcos37*t
hf=hi+Vi*t-4.9t^2
0=380-Vsin37*t-4.9t^2 t is given at 4 seconds, solve for V.
horizontal distance:Vcos37*t
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.