Asked by applebottom
                A plane dives at 37° to the horizontal and releases a package at an altitude of 380m. If the load is in the air for 4s, find: 
a) the speed of the plane when it released the package;
 
b) the horizontal distance traveled by the package after it is released.
 
            
            
        a) the speed of the plane when it released the package;
b) the horizontal distance traveled by the package after it is released.
Answers
                    Answered by
            bobpursley
            
    Vertical speed initial: -Vsin37
hf=hi+Vi*t-4.9t^2
0=380-Vsin37*t-4.9t^2 t is given at 4 seconds, solve for V.
horizontal distance:Vcos37*t
    
hf=hi+Vi*t-4.9t^2
0=380-Vsin37*t-4.9t^2 t is given at 4 seconds, solve for V.
horizontal distance:Vcos37*t
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