Asked by Adam

A fighter pilot dives his plane toward the ground at 345 m/s. He pulls out of the dive on a vertical circle. What is the minimum radius of the circle, so that the normal force exerted on the pilot by his seat never exceeds three times his weight?

Answers

Answered by bobpursley
3mg>mv^2/r

solve for r
Answered by Adam
my answer was wrong.. I got 4048.47? What did you get?
Answered by bobpursley
oops. Normal force on his seat includes his weight.

3mg>mg+mv^2/r
Answered by Ingrid
So then... once you divide out the m's it would be 3g>g+v^2/r?
Answered by bobpursley
yes.
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