Asked by Adam
A fighter pilot dives his plane toward the ground at 345 m/s. He pulls out of the dive on a vertical circle. What is the minimum radius of the circle, so that the normal force exerted on the pilot by his seat never exceeds three times his weight?
Answers
Answered by
bobpursley
3mg>mv^2/r
solve for r
solve for r
Answered by
Adam
my answer was wrong.. I got 4048.47? What did you get?
Answered by
bobpursley
oops. Normal force on his seat includes his weight.
3mg>mg+mv^2/r
3mg>mg+mv^2/r
Answered by
Ingrid
So then... once you divide out the m's it would be 3g>g+v^2/r?
Answered by
bobpursley
yes.
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