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a 110 kg person dives off a cliff and hits the water at 17 m/s. how high is the cliff?
13 years ago

Answers

Steve
v = sqrt(2as)
17 = sqrt(2*9.8s)
289 = 19.6s
s = 14.7m

note that the mass of the diver does not matter in this problem.
13 years ago

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