Asked by luis
a 110 kg person dives off a cliff and hits the water at 17 m/s. how high is the cliff?
Answers
Answered by
Steve
v = sqrt(2as)
17 = sqrt(2*9.8s)
289 = 19.6s
s = 14.7m
note that the mass of the diver does not matter in this problem.
17 = sqrt(2*9.8s)
289 = 19.6s
s = 14.7m
note that the mass of the diver does not matter in this problem.
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