Asked by jake
A submarine dives down to a depth 9.5 beneath the surface of the ocean. Calculate the pressure in atmospheres at that depth, assuming the density of water is 1029 kg/m3, and the air pressure at the surface is 101.5 kPa
Answers
Answered by
Damon
101.5 * 10*3 + 1029 *9.81 * 9.5
= 101.5 * 10^3 + 95.898 * 10^3
= 197 k Pa
or about 2 atmospheres
note, 30 feet deep is about additional atmosphere
= 101.5 * 10^3 + 95.898 * 10^3
= 197 k Pa
or about 2 atmospheres
note, 30 feet deep is about additional atmosphere
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