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416g of an anhydrous Bacl2 were obtained when 488g of hydrated salt were heated.calculate x in the formula:Bacl2.xH2O

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g H2O = 488 - 416 = 72
mols BaCl2 = 416/molar mass BaCl2 = approx 2
mols H2O = 72/18 = approx 4
Reduce to lowest terms.
BaCl2.2H2O

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