415 WHAT? 459 WHAT? tons? miles? km? I will assume you meant grams. Also, I assume you meant to write "were" instead of "where".
BaCl2.xH2O ==> BaCl2 + xH2O
459 g.....................415.........x grams
grams H2O in the hydrate = 459 - 415 = 44
mols BaCl2 = grams/molar mass = 415/208.3 = 1.99
mols H2O = 44/18 = 2.44
Then per 1 mole BaCl2 we have 2.44/1.99 = 1.23 moles H2O and the formula would be BaCl2.1.23H2O. You need to look at your data because the accepted value is BaCl2.2H2O.
415 anhydrous barium chloride where obtained when 459 of hydrated salt where heated. calculate n in the formula bacl2 .nh2 o
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