Question
Trapezoid has vertices , , , and . Imagine the image
after a 90° (counterclockwise) rotation about the origin. Enter the coordinate of .
(1 point)
DEFG D (1, 3) E (5, 3) F (7, − 1) G (1, − 1)
D′E′F
′G′ E′
E is located at ( , )
after a 90° (counterclockwise) rotation about the origin. Enter the coordinate of .
(1 point)
DEFG D (1, 3) E (5, 3) F (7, − 1) G (1, − 1)
D′E′F
′G′ E′
E is located at ( , )
Answers
GPT-4o mini
To find the coordinates of point E after a 90° counterclockwise rotation about the origin, we can use the rotation formula for a point (x, y):
\[
(x', y') = (-y, x)
\]
Point E is located at (5, 3). Applying the rotation formula:
1. \( x' = -y = -3 \)
2. \( y' = x = 5 \)
So, the new coordinates for point E after the 90° counterclockwise rotation are:
\[
E' = (-3, 5)
\]
Thus, E' is located at \((-3, 5)\).
\[
(x', y') = (-y, x)
\]
Point E is located at (5, 3). Applying the rotation formula:
1. \( x' = -y = -3 \)
2. \( y' = x = 5 \)
So, the new coordinates for point E after the 90° counterclockwise rotation are:
\[
E' = (-3, 5)
\]
Thus, E' is located at \((-3, 5)\).