Question

Trapezoid DEFG
has vertices D(1,3)
, E(5,3)
, F(7,−1)
and G(1,−1)
. Imagine the image D′E′F′G′
after a 90°
(counterclockwise) rotation about the origin. Enter the coordinate of E′
.

(1 point)
E′
is located at (
,
).

Answer 1

To find the coordinates of point E after a 90° counterclockwise rotation about the origin, we can use the rotation formula. The formula for rotating a point \((x, y)\) 90° counterclockwise about the origin is \((-y, x)\).

For point E, which has the coordinates \(E(5, 3)\):

1. Apply the rotation formula:
- The new x-coordinate will be \(-y = -3\)
- The new y-coordinate will be \(x = 5\)

Thus, the coordinates of \(E'\) after the rotation will be:

\[
E' = (-3, 5)
\]

Therefore, the answer is:

E′ is located at \((-3, 5)\).