The Zero Power Rule states that any non-zero number raised to the power of 0 is equal to 1.
Let's apply this rule to the expression \( 9 \cdot (-33)^0 + \frac{3}{2}(8 - 27^0) \).
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First, calculate \((-33)^0\): \[ (-33)^0 = 1 \] Therefore, \( 9 \cdot (-33)^0 = 9 \cdot 1 = 9 \).
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Next, calculate \(27^0\): \[ 27^0 = 1 \] So, we have \( 8 - 27^0 = 8 - 1 = 7 \).
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Now calculate \(\frac{3}{2}(7)\): \[ \frac{3}{2} \cdot 7 = \frac{21}{2} \]
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Finally, combine both parts: \[ 9 + \frac{21}{2} \]
To add these, convert \(9\) into a fraction: \[ 9 = \frac{18}{2} \]
Now add them together: \[ \frac{18}{2} + \frac{21}{2} = \frac{18 + 21}{2} = \frac{39}{2} \]
Thus, the equivalent expression is \[ \frac{39}{2} \]