Question

apply the Zero Power Rule to create an equivalent expression to (−40)to the0power + 1/2(11−320) (2 points) (−40)to the0power + 12(11−320) = +1/2 ( − )

Answer 1

The Zero Power Rule states that any non-zero number raised to the power of 0 is equal to 1. Therefore, we can simplify \((-40)^0\) as follows:

\[
(-40)^0 = 1
\]

Now, we can substitute that into the given expression:

\[
(-40)^0 + \frac{1}{2}(11 - 320)
\]

This simplifies to:

\[
1 + \frac{1}{2}(11 - 320)
\]

Now let's simplify \((11 - 320)\):

\[
11 - 320 = -309
\]

Now, substitute that back into the expression:

\[
1 + \frac{1}{2}(-309)
\]

Next, calculate \(\frac{1}{2}(-309)\):

\[
\frac{1}{2}(-309) = -\frac{309}{2}
\]

Now combine that with 1:

\[
1 - \frac{309}{2} = \frac{2}{2} - \frac{309}{2} = \frac{2 - 309}{2} = \frac{-307}{2}
\]

Thus, the simplified expression is:

\[
\frac{-307}{2}
\]

So the final answer after applying the Zero Power Rule is:

\[
\frac{-307}{2}
\]