The Zero Power Rule states that any non-zero number raised to the power of 0 equals 1. Therefore:
\[
(-40)^0 = 1
\]
and
\[
32^0 = 1
\]
Now, substituting these values into the original expression:
\[
(-40)^0 + \frac{1}{2}(11 - 32^0) = 1 + \frac{1}{2}(11 - 1)
\]
Now, simplifying inside the parentheses:
\[
11 - 1 = 10
\]
So, we have:
\[
1 + \frac{1}{2}(10)
\]
Now, calculating \(\frac{1}{2}(10)\):
\[
\frac{1}{2} \times 10 = 5
\]
Now we can write the expression:
\[
1 + 5
\]
Rearranging this according to your format gives:
\[
(-40)^0 + \frac{1}{2}(11 - 32^0) = 1 + \frac{1}{2}(11 - 1) = 1 + \frac{1}{2}(10) = 1 + 5
\]
Thus, the equivalent expression is:
\[
1 + \frac{1}{2}(10)
\]
So, filling in the blanks, we have:
\[
1 + \frac{1}{2}(11 - 1)
\]
Thus the final answer is:
\[
1 + \frac{1}{2}(11 - 1)
\]
So your completion for the expression format would be:
(−40)^0 + 1/2(11−32^0) = 1 + 1/2(11 − 1)