Question

3 wholes and 3 fiths minus 2 holes and 4 fiths

Answer 1

To solve the problem, we first need to represent the whole numbers and fractions clearly.

1. Convert the mixed numbers into improper fractions:
- \(3\) wholes and \(3\) fifths can be written as:
\[
3 \frac{3}{5} = \frac{3 \times 5 + 3}{5} = \frac{15 + 3}{5} = \frac{18}{5}
\]
- \(2\) wholes and \(4\) fifths can be written as:
\[
2 \frac{4}{5} = \frac{2 \times 5 + 4}{5} = \frac{10 + 4}{5} = \frac{14}{5}
\]

2. Now, we need to subtract these two improper fractions:
\[
\frac{18}{5} - \frac{14}{5}
\]
Since the denominators are the same, we can subtract the numerators:
\[
\frac{18 - 14}{5} = \frac{4}{5}
\]

Thus, the result of \(3\) wholes and \(3\) fifths minus \(2\) wholes and \(4\) fifths is \(\frac{4}{5}\).