3 wholes and 3 fiths minus 2 holes and 4 fiths

1 answer

To solve the problem, we first need to represent the whole numbers and fractions clearly.

  1. Convert the mixed numbers into improper fractions:

    • \(3\) wholes and \(3\) fifths can be written as: \[ 3 \frac{3}{5} = \frac{3 \times 5 + 3}{5} = \frac{15 + 3}{5} = \frac{18}{5} \]
    • \(2\) wholes and \(4\) fifths can be written as: \[ 2 \frac{4}{5} = \frac{2 \times 5 + 4}{5} = \frac{10 + 4}{5} = \frac{14}{5} \]
  2. Now, we need to subtract these two improper fractions: \[ \frac{18}{5} - \frac{14}{5} \] Since the denominators are the same, we can subtract the numerators: \[ \frac{18 - 14}{5} = \frac{4}{5} \]

Thus, the result of \(3\) wholes and \(3\) fifths minus \(2\) wholes and \(4\) fifths is \(\frac{4}{5}\).