Question

5 minus 3 wholes and 2 sevenths

Answer 1

To solve the expression "5 minus 3 wholes and 2 sevenths," we first need to convert the mixed number (3 wholes and 2 sevenths) into an improper fraction.

1. Convert 3 wholes into sevenths:
\[
3 = \frac{3 \times 7}{7} = \frac{21}{7}
\]

2. Now, add the 2 sevenths to this:
\[
3 \text{ wholes and } 2 \text{ sevenths} = \frac{21}{7} + \frac{2}{7} = \frac{23}{7}
\]

Next, we perform the subtraction:
\[
5 - \frac{23}{7}
\]

To subtract, we can convert 5 into a fraction with a denominator of 7:
\[
5 = \frac{5 \times 7}{7} = \frac{35}{7}
\]

Now we perform the subtraction:
\[
\frac{35}{7} - \frac{23}{7} = \frac{35 - 23}{7} = \frac{12}{7}
\]

The result, \(\frac{12}{7}\), can be expressed as a mixed number:
\[
\frac{12}{7} = 1 \frac{5}{7}
\]

Thus, the final answer is:
\[
5 - 3 \text{ wholes and } 2 \text{ sevenths} = 1 \frac{5}{7}
\]