Question

9 wholes and 5 sevenths plus 1 whole and 1 fourth

Answer 1

To add \(9\) wholes and \(5\) sevenths with \(1\) whole and \(1\) fourth, we can break the problem into two parts: the whole numbers and the fractional parts.

1. **Whole Numbers:**
\[
9 + 1 = 10
\]

2. **Fractional Parts:**
We need to add \( \frac{5}{7} \) and \( \frac{1}{4} \). To do that, we have to find a common denominator. The least common multiple of \(7\) and \(4\) is \(28\).

Converting each fraction:
\[
\frac{5}{7} = \frac{5 \times 4}{7 \times 4} = \frac{20}{28}
\]
\[
\frac{1}{4} = \frac{1 \times 7}{4 \times 7} = \frac{7}{28}
\]

Now we can add the converted fractions:
\[
\frac{20}{28} + \frac{7}{28} = \frac{27}{28}
\]

3. **Combine Whole Numbers and Fractions:**
Now, we combine the results:
\[
10 + \frac{27}{28} = 10 \frac{27}{28}
\]

Thus, the result of \(9\) wholes and \(5\) sevenths plus \(1\) whole and \(1\) fourth is:
\[
\boxed{10 \frac{27}{28}}
\]