Question

4 wholes and 7 nignths minus five sixths

Answer 1

To subtract \( \frac{5}{6} \) from \( 4 \frac{7}{9} \), we first convert the mixed number into an improper fraction.

1. **Convert \( 4 \frac{7}{9} \) to an improper fraction:**
\[
4 \frac{7}{9} = \frac{(4 \times 9) + 7}{9} = \frac{36 + 7}{9} = \frac{43}{9}
\]

2. **Now, subtract \( \frac{5}{6} \) from \( \frac{43}{9} \):**
To perform the subtraction, we need a common denominator. The denominators are 9 and 6, and the least common multiple (LCM) of 9 and 6 is 18.

3. **Convert both fractions to have a denominator of 18:**
\[
\frac{43}{9} = \frac{43 \times 2}{9 \times 2} = \frac{86}{18}
\]
\[
\frac{5}{6} = \frac{5 \times 3}{6 \times 3} = \frac{15}{18}
\]

4. **Now perform the subtraction:**
\[
\frac{86}{18} - \frac{15}{18} = \frac{86 - 15}{18} = \frac{71}{18}
\]

5. **Convert \( \frac{71}{18} \) back to a mixed number:**
To convert \( \frac{71}{18} \) to a mixed number, divide 71 by 18:
\[
71 \div 18 = 3 \quad (\text{remainder } 17)
\]
Thus, \( \frac{71}{18} = 3 \frac{17}{18} \).

Therefore, \( 4 \frac{7}{9} - \frac{5}{6} = 3 \frac{17}{18} \).