To solve "1 whole minus 10 ninths," you can first express 1 as a fraction with the same denominator as 10 ninths.
1 can be written as \( \frac{9}{9} \) since \( 9/9 = 1 \).
Now, subtract \( \frac{10}{9} \) from \( \frac{9}{9} \):
\[ \frac{9}{9} - \frac{10}{9} = \frac{9 - 10}{9} = \frac{-1}{9} \]
So, \( 1 - \frac{10}{9} = -\frac{1}{9} \).