Asked by Emily
A police car stopped at a set of lights has a speeder pass it at 100 km/h. If the police car can accelerate at 3.6 m/s^2, how long does it take to catch the speeder?
Answers
Answered by
bobpursley
They to the same distance in the same time.
d=100km/hr*t
d=1/2 3.6m/s^2 t
change km/hr to m/s in the first equation, then set d=d, and solve for t.
d=100km/hr*t
d=1/2 3.6m/s^2 t
change km/hr to m/s in the first equation, then set d=d, and solve for t.
Answered by
Rayan
Why do you multiply by 1/2?
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