Asked by Marcy
A 4.5 g bullet is stopped in a block of wood (m= 5.04 kg). The speed of the bullet-plus-wood combination immediately after the collision is 0.298 m/s. What is the original speed of the bullet? Answer in m/s.
I did it like this and got it wrong:
mv=MV
.298= (.0045kg)(velocity)
66.2 m/s= velocity
What did I do wrong? What do I need to do?
I did it like this and got it wrong:
mv=MV
.298= (.0045kg)(velocity)
66.2 m/s= velocity
What did I do wrong? What do I need to do?
Answers
Answered by
Damon
.0045 kg bullet at speed v
5.04 kg block at speed 0
initial momentum = .0045 v
final momentum = ( 5.04 + .0045)(.298)
so
.0045 v = 1.50
v = 334 m/s
5.04 kg block at speed 0
initial momentum = .0045 v
final momentum = ( 5.04 + .0045)(.298)
so
.0045 v = 1.50
v = 334 m/s
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