Asked by Mary
a 3262 kg car starts from rest at the top of a 5m long driveway that is sloped at 20 degrees with the horizontal. If an average friction force of 612N impedes the motion, fing the speed of the car at the bottom of the driveway.
Answers
Answered by
bobpursley
Do this with energy:
KEtop + PEtop =KEbottom+PEbottom + frictionwork
0+mgh = 1/2 m v^2 +0 + 612*5
h= 5sin20
solve for v
KEtop + PEtop =KEbottom+PEbottom + frictionwork
0+mgh = 1/2 m v^2 +0 + 612*5
h= 5sin20
solve for v