Asked by Cindy
For the reaction:
2MnO2+ 4KOH+ O2+ Cl2 yields 2KMnO4+ 2KCL+ 2H20
there is 100. g of each reactant available. Which reagent is the limiting reactant?
2MnO2+ 4KOH+ O2+ Cl2 yields 2KMnO4+ 2KCL+ 2H20
there is 100. g of each reactant available. Which reagent is the limiting reactant?
Answers
Answered by
bobpursley
convert each 100 g to moles.
Then divide the mole of each by the coefficent for the reactant. The lowest number is your limiting reactant.
Then divide the mole of each by the coefficent for the reactant. The lowest number is your limiting reactant.
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