For the reaction:

Question

2MnO2+ 4KOH+ O2+ Cl2 yields 2KMnO4+ 2KCL+ 2H20
there is 100. g of each reactant available. Which reagent is the limiting reactant?

Answer 1

convert each 100 g to moles.
Then divide the mole of each by the coefficent for the reactant. The lowest number is your limiting reactant.