Asked by David
Consider the reaction: K2S(aq)+Co(NO3)2(aq)=2KNO3(aq)+CoS(s) what volume of 0.255 M K2S solution is required to completely react with 160 mL of 0.130 M
Co(NO3)2?
Co(NO3)2?
Answers
Answered by
DrBob222
I have copied the equation without the phases to save space.
K2S + Co(NO3)2 = 2KNO3 + CoS
mols Co(NO3)2 = M x L = ?
Using the coefficients in the balanced equation, convert mols Col(NO3)2 to mols K2S. Since the coefficients are the same then mols Co(NO3)2 = mols K2S.
Then M K2S = mols K2S/L K2S. You know mols and M, solve for L and convert to mL if needed.
K2S + Co(NO3)2 = 2KNO3 + CoS
mols Co(NO3)2 = M x L = ?
Using the coefficients in the balanced equation, convert mols Col(NO3)2 to mols K2S. Since the coefficients are the same then mols Co(NO3)2 = mols K2S.
Then M K2S = mols K2S/L K2S. You know mols and M, solve for L and convert to mL if needed.
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