Asked by jerr

A 5.4 g bullet leaves the muzzle of a rifle with a speed of 334 m/s. What force (assumed constant) is exerted on the bullet while it is traveling down the 0.95 m long barrel of the rifle?
___N

Answers

Answered by Henry
d = rt,
t = d/r = 0.95 m / 334 m/s = 0.0028 s,

V = at,
a = V/t = 334 m/s / 0.0028 s = 117606 m/s^2,

F = ma = 0.0054 kg * 117606 m/s^2 =
6351 N.


Answered by Ash
State the law of acceleration in its full form and give examples of how it works
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