Asked by Elisa
A 4.0 g bullet leaves the muzzle of a rifle with a speed of 310 m/s. What force (assumed constant) is exerted on the bullet while it is traveling down the 0.9 m long barrel of the rifle?
Answers
Answered by
drwls
Force x distance = Work done on bullet
= kinetic energy increase = (1/2)MV^2
Solve for the Force
= kinetic energy increase = (1/2)MV^2
Solve for the Force
Answered by
Elisa
Hello. I keep repeating the problem and I get a huge number.
Answered by
drwls
Show your work. Make sure the mass of the bullet is converted to kg.
F = (1/2) M V^2 / (0.9 m)
The answer will be in Newtons if m is in kg and V is in m/s.
F = (1/2) M V^2 / (0.9 m)
The answer will be in Newtons if m is in kg and V is in m/s.
Answered by
Elisa
it worked now.. thank you.. i forgot to convert!
Answered by
j
A force of 2.3 N is exerted on a 6.6 g rifle bullet. What is the bullet's acceleration
Answered by
amanda
A 4.1-g bullet leaves the muzzle of a rifle with a speed of 300 m/s. What force (assumed constant) is exerted on the bullet while it is traveling down the 0.81-m-long barrel of the rifle?
Answered by
shakthee
my answer is 214N. is that right?
Answered by
Attiq ur rehman
rigth
Answered by
Attiq ur rehman
right
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