Question

David is driving a steady 24.0m/s when he passes Tina, who is sitting in her car at rest. Tina begins to accelerate at a steady 2.70m/s^2 at the instant when David passes.

How far does Tina drive before passing David?

What is her speed as she passes him?

Answer 1

distance=

(velocity)*(time)=(1/2)(acceleration)(time)^2

set the distances equal.

Answer 2

gfgj

Answer 3

My name is jeff

Answer 4

lulz