Question
How many grams of perchloric acid,HClO4, are contained in 37.6g of 70.5wt% aqueous perchloric acid? How many grand of water are in the same solution? C=1g/mol; Cl=35.5g/mol;O =16g/mol
Answers
GPT-4o mini
To find out how many grams of perchloric acid (HClO₄) and water are contained in a solution of 37.6 g of 70.5 wt% aqueous perchloric acid, we can follow these steps:
1. **Calculate the mass of perchloric acid in the solution**:
The percentage concentration by weight tells us that 70.5% of the solution is HClO₄. Therefore, the mass of HClO₄ in the solution can be found by multiplying the total mass of the solution by the percentage concentration:
\[
\text{Mass of HClO}_4 = \text{Total mass of solution} \times \frac{\text{wt\% of HClO}_4}{100}
\]
\[
\text{Mass of HClO}_4 = 37.6 \, \text{g} \times \frac{70.5}{100}
\]
\[
\text{Mass of HClO}_4 = 37.6 \, \text{g} \times 0.705 = 26.51 \, \text{g} \, \text{(rounded to two decimal places)}
\]
2. **Calculate the mass of water in the solution**:
To find the mass of water in the same solution, we would subtract the mass of perchloric acid from the total mass of the solution:
\[
\text{Mass of Water} = \text{Total mass of solution} - \text{Mass of HClO}_4
\]
\[
\text{Mass of Water} = 37.6 \, \text{g} - 26.51 \, \text{g} = 11.09 \, \text{g} \, \text{(rounded to two decimal places)}
\]
### Final Results:
- The mass of perchloric acid (HClO₄) in the solution is approximately **26.51 g**.
- The mass of water in the solution is approximately **11.09 g**.
1. **Calculate the mass of perchloric acid in the solution**:
The percentage concentration by weight tells us that 70.5% of the solution is HClO₄. Therefore, the mass of HClO₄ in the solution can be found by multiplying the total mass of the solution by the percentage concentration:
\[
\text{Mass of HClO}_4 = \text{Total mass of solution} \times \frac{\text{wt\% of HClO}_4}{100}
\]
\[
\text{Mass of HClO}_4 = 37.6 \, \text{g} \times \frac{70.5}{100}
\]
\[
\text{Mass of HClO}_4 = 37.6 \, \text{g} \times 0.705 = 26.51 \, \text{g} \, \text{(rounded to two decimal places)}
\]
2. **Calculate the mass of water in the solution**:
To find the mass of water in the same solution, we would subtract the mass of perchloric acid from the total mass of the solution:
\[
\text{Mass of Water} = \text{Total mass of solution} - \text{Mass of HClO}_4
\]
\[
\text{Mass of Water} = 37.6 \, \text{g} - 26.51 \, \text{g} = 11.09 \, \text{g} \, \text{(rounded to two decimal places)}
\]
### Final Results:
- The mass of perchloric acid (HClO₄) in the solution is approximately **26.51 g**.
- The mass of water in the solution is approximately **11.09 g**.