Asked by CRIS
A 25.0 mL sample of perchloric acid solution required 45.3 mL of 0.101 sodium hydroxide solution for complete neutralization. what was the concentration of the perchloric acide solution?
work:
0.0453 L NaOH x ( .101 mol NaOH/ 1L NaOH) x (1 mol HClO4/ 1 mol NaOH) x (25.0 mL HClO4/ 1 mol HClO4) = .114
.114 x 100%= 11.4
I have no clue if I did that right. Thank you
work:
0.0453 L NaOH x ( .101 mol NaOH/ 1L NaOH) x (1 mol HClO4/ 1 mol NaOH) x (25.0 mL HClO4/ 1 mol HClO4) = .114
.114 x 100%= 11.4
I have no clue if I did that right. Thank you
Answers
Answered by
bobpursley
Va*Ma=Vb*Mb
Ma=Vb/Va *Mb=43.3/25 *.101=.17M check that
Ma=Vb/Va *Mb=43.3/25 *.101=.17M check that
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