Question

430 mL of 0.044 M perchloric acid is added to 681 mL of 0.085 M hydroiodic acid. Calculate the pH of the resulting solution of strong acids at 25 °C.

Please help.
I am confused on how to do this

Answer 1

what is wrong with computing the conc H+ due to each acid, then adding them, and from that sum H+, calculating pH?

Answer 2

I did that! but my answer was wrong