CuSO4 + 2KOH ==> Cu(OH)2 + K2SO4
You have 150 x 1.50 = 225 millimols CuSO4
and 450 mmols KOH
q = mass solution x specific heat x (Tfinal-Tinitia)
I would use 300 mL = 300 g for mass soln.
Specific heat H2O is 4.184 J/g*C
Tfinal and Tinitial are given.
q is Joules/225 mmols. Convert to kJ/mol
A 150.0 mL sample of a 1.50 M solution of CuSO4
is mixed with a 150.0 mL sample of 3.00 M
KOH in a coffee cup calorimeter. The temperature of both solutions and the calorimeter was
25.2°C before mixing and 31.3°C after mixing. The heat capacity of the calorimeter is 24.2 J/K.
Calculate the ΔHrxn for this reaction in units of kJ / mol of copper (II) hydroxide (19 points). Assume
the solutions is dilute enough that the specific heat and density of the solution is the same as that
of water (
2 answers
34J