Question

The hypotenuse of a right triangle is 22 m long. The length of one leg is 10 m less than the other. Find the lengths of the legs.
I have so far
let one leg be x
the other leg will be x-10
x^2 +(x-10)^2=22^2
x^2+x^2-20x+100=484

Answer 1

carry on ...
x^2+x^2-20x+100=484
2x^2 - 20x - 384 = 0
x^2 - 10x - 192 = 0
I used the formula to solve for x

x = 19.7309

one side is 19.7309, the other 9.7309

Answer 2

x^2+x^2-20x+100=484

--> 2x^2-20x-384=0

--> x^2-10x-192=0

Now apply quadratic formula.