Question

the molar heat of fusion for water is 6.01 kJ/mol. the heat capacity for water is 75 J/mol deg. Which expresssion gives the quantity of energy needed to change one mol ice at 0 degrees celsius to liquid water at 25 degrees celsius?

a.)6010/(75x25)
b.)6.01+75
c.)6010+(75+25)
d.)(6010/298)+(75x25)
e.)(6010+(75x25))/298

Answer 1

q1 = heat to melt ice at zero C to water at zero C.
q1 = mass ice x heat fusion.

q2 = heat to move from zero C to 25 C.
q2 = mass water x specific heat water x delta T.

q total = q1 + q2
I don't see the right answer listed. Perhaps you made a typo in answer c.

Answer 2

Yeah i meant to put 6010+(75x25). That would be correct right? And thank you for all your help.

Answer 3

Yes. That would be correct. I should get extra points for that; i.e., some for the right answer and some for catching the typo. :-)