Asked by Anonymous
Heat of fusion of ice lab
Initial mass of empty cup calorimeter 9.55g
Initial mass of water 200.15g
Initial mass of ice + water 209.7g
Initial temp of water 41.9°C
Initial mass of ice 26.9g
Final mass of cup 9.55g
Final mass of water 227.05g
Final mass of cup + water 236.6g
Final temp of water 26.9°C
Calculate the heat of fusion of ice
Answers
Answered by
bobpursley
the sum of heats gained is zero. You will need the specific heat of the calorimeter.
Heats gained:
calorimeter=9.55*Ccal*(26.9-41.9)
water= 200.15*cwater(26.9-41.9)
icemelting=Hfice*9.7
this assumes the inital temp of ice was 0C
meltedicewater=9.7*Cwater*(26.9-0)
add all those (some are negative, some are positive), set equal to zero, then solve for Hfice
Heats gained:
calorimeter=9.55*Ccal*(26.9-41.9)
water= 200.15*cwater(26.9-41.9)
icemelting=Hfice*9.7
this assumes the inital temp of ice was 0C
meltedicewater=9.7*Cwater*(26.9-0)
add all those (some are negative, some are positive), set equal to zero, then solve for Hfice
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