Question

How many moles of Li2CO3 can be formed when 3.13 moles of CO2 react with excess LiOH according to the equation ?

CO2 + 2LiOH --> Li2OH + H2O

Responses

3.13 mol
3.13 mol

12.52 mol
12.52 mol

1.565 mol
1.565 mol

6.26 mol
6.26 mol

Answer 1

To determine how many moles of Li2CO3 can be formed from 3.13 moles of CO2 reacting with excess LiOH, we first need to clarify the reaction based on the provided equation:

The balanced equation is:

\[
\text{CO}_2 + 2\text{LiOH} \rightarrow \text{Li}_2\text{CO}_3 + \text{H}_2\text{O}
\]

From the balanced equation, we can see that 1 mole of CO2 reacts with 2 moles of LiOH to produce 1 mole of Li2CO3.

Therefore, the stoichiometry of the reaction shows that 1 mole of CO2 produces 1 mole of Li2CO3.

Given that you have 3.13 moles of CO2, it will produce the same amount of Li2CO3:

\[
3.13 \text{ moles of CO}_2 \rightarrow 3.13 \text{ moles of Li}_2\text{CO}_3
\]

So, the correct response is:

**3.13 mol**