Question

How many moles of Li2CO3 can be formed when 3.13 moles of CO2 react with excess LiOH according to the equation ?

CO2 + 2LiOH --> Li2OH + H2O

Responses

3.13 mol
3.13 mol

1.565 mol
1.565 mol

6.26 mol
6.26 mol

12.52 mol

Answer 1

The balanced chemical equation for the reaction is:

\[
\text{CO}_2 + 2 \text{LiOH} \rightarrow \text{Li}_2\text{CO}_3 + \text{H}_2\text{O}
\]

From the balanced equation, we can see that 1 mole of CO2 reacts with 2 moles of LiOH to produce 1 mole of Li2CO3.

Given that you have 3.13 moles of CO2, we can determine how many moles of Li2CO3 can be produced. According to the stoichiometry of the reaction:

1 mole of CO2 → 1 mole of Li2CO3

Thus, the number of moles of Li2CO3 formed from 3.13 moles of CO2 is:

\[
\text{Moles of Li}_2\text{CO}_3 = \text{Moles of CO}_2 = 3.13 \text{ mol}
\]

Therefore, the correct answer is:

**3.13 mol**.