How do I disassociate Li2CO3
I have tried Li_2CO_3--> 2Li^+ + 3CO^2-
What am I doing wrong?
6 answers
2Li2CO3 -> 4Li+2CO2+O2
So I have to balance the equation?
The dissociation rules are:
-oxidation numbers become the charge
-subscripts become coefficients
-groups stay together
-no break up of weak acids, weak bases or insolubles.
I tried to type in the answer and the computer didn't like it. Could my problem be that this is a "weak" compound?
The dissociation rules are:
-oxidation numbers become the charge
-subscripts become coefficients
-groups stay together
-no break up of weak acids, weak bases or insolubles.
I tried to type in the answer and the computer didn't like it. Could my problem be that this is a "weak" compound?
yes you always need to balance the equation.It's in the law of conservation of mass..
Both of you are wrong. The dissociastion for Li2CO3 is as follows:
Li2CO3 ==> 2Li^+ + CO3^2-
Li2CO3 ==> 2Li^+ + CO3^2-
Some metallic carbonates, when heated, decompose to form the metal oxide and carbon dioxide,
so:
Li2CO3 ---> Li2O + CO2
so:
Li2CO3 ---> Li2O + CO2
That is correct. Many metallic carbonates do decompose to CO2 and the metal oxide (as in your equation for Li2CO3); however, the original question was for the dissociation of Li2CO3 and not for heating Li2CO3.
3 answers