Asked by Anita
How do I disassociate Li2CO3
I have tried Li_2CO_3--> 2Li^+ + 3CO^2-
What am I doing wrong?
I have tried Li_2CO_3--> 2Li^+ + 3CO^2-
What am I doing wrong?
Answers
Answered by
kazz
2Li2CO3 -> 4Li+2CO2+O2
Answered by
Anita
So I have to balance the equation?
The dissociation rules are:
-oxidation numbers become the charge
-subscripts become coefficients
-groups stay together
-no break up of weak acids, weak bases or insolubles.
I tried to type in the answer and the computer didn't like it. Could my problem be that this is a "weak" compound?
The dissociation rules are:
-oxidation numbers become the charge
-subscripts become coefficients
-groups stay together
-no break up of weak acids, weak bases or insolubles.
I tried to type in the answer and the computer didn't like it. Could my problem be that this is a "weak" compound?
Answered by
kazz
yes you always need to balance the equation.It's in the law of conservation of mass..
Answered by
DrBob222
Both of you are wrong. The dissociastion for Li2CO3 is as follows:
Li2CO3 ==> 2Li^+ + CO3^2-
Li2CO3 ==> 2Li^+ + CO3^2-
Answered by
kazz
Some metallic carbonates, when heated, decompose to form the metal oxide and carbon dioxide,
so:
Li2CO3 ---> Li2O + CO2
so:
Li2CO3 ---> Li2O + CO2
Answered by
DrBob222
That is correct. Many metallic carbonates do decompose to CO2 and the metal oxide (as in your equation for Li2CO3); however, the original question was for the dissociation of Li2CO3 and not for heating Li2CO3.
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