Question
What is the formula weight of Li2CO3?
73.891 amu
b. What is the mass of 1.30 x 10-4 mol of Li2CO3?
9.61E-3
c. How many moles of CO32- ions are present in 102 g of Li2CO3?
Dont get how to compute
73.891 amu
b. What is the mass of 1.30 x 10-4 mol of Li2CO3?
9.61E-3
c. How many moles of CO32- ions are present in 102 g of Li2CO3?
Dont get how to compute
Answers
DrBob222
102g Li2CO3 x (1 mol Li2CO3/73.891g Li2CO3) x (1 mol CO3^2-/1 mol Li2CO3) = ?
The first term (102 x 1/73.891 converts 102 g Li2CO3 to moles Li2CO3. The second term tells you that there is 1 mol CO3^2- ions in 1 mol Li2CO3, another way of saying that since there is 1 mole CO3/mol Li2CO3 then moles Li2CO3 = mol CO3^2-
The first term (102 x 1/73.891 converts 102 g Li2CO3 to moles Li2CO3. The second term tells you that there is 1 mol CO3^2- ions in 1 mol Li2CO3, another way of saying that since there is 1 mole CO3/mol Li2CO3 then moles Li2CO3 = mol CO3^2-
krystal
so the answer would be 1.38 moles
DrBob222
yes