Asked by Cheyenne
Calculate the molality of acetone in an aqueous solution with a mole fraction for acetone of 0.235. Answer in units of m.
Answers
Answered by
DrBob222
acetone = Ac2O
I would try something like this.
Take some value of g H2O, say 18 g (you may need to use more precise numbers than I).
moles H2O = 18/18 = 1 mole.
Then X<sub>H2O</sub> = 0.765 = (1 mole H2O/1 mole H2O + x moles Ac2O).
Solve for x moles Ac2O. Convert mols Ac2O to grams Ac2O remembering g = mols x molar mass.
Now you have grams water and mole Ac2O, molality = moles/kg solvent.
Post your work if you get stuck.
I would try something like this.
Take some value of g H2O, say 18 g (you may need to use more precise numbers than I).
moles H2O = 18/18 = 1 mole.
Then X<sub>H2O</sub> = 0.765 = (1 mole H2O/1 mole H2O + x moles Ac2O).
Solve for x moles Ac2O. Convert mols Ac2O to grams Ac2O remembering g = mols x molar mass.
Now you have grams water and mole Ac2O, molality = moles/kg solvent.
Post your work if you get stuck.
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