Question

Calculate the molality of a 1.00% by weight sulfuric acid solution if the density of the solution is 1.0054 g/mL.

thanks for your help!

Answer 1

1.0054 g/mL x 1000 mL x 0.01 = 10.054 g H2SO4.
Convert that mols. 10.054 x (1 mol/98g) = ?mols H2SO4.
mass of 1000 mL = 1.0054 x 1000 nK - 1005.4
g solvent = 1005.4-10.054 = ?
Then m = mols/kg solvent.