48.2g of KBr/(100g-48.2g)*(mole/119.002 g)= moles of KBr/Solvent in g
moles of KBr/Solvent in g*(1g/10^-3kg)= molality of solution <=== 3 Sig figs
Calculate the molality of 48.2 percent by mass KBr solution?
1 answer
1 answer