Question

1. Calculate the MOLALITY (m=mol/kg) of the salt water solution. Note: Include the mass of ice AND volume of water when calculating the TOTAL MASS of the solvent (water). (1ml of water=1g of water.
Is my work correct? So what I did was,
Knowing m=mol/kg for molality, the following that has been measured include: mass of ice (50.51 g ICE), mass of NaCl(9.059 g NaCl), volume of water (100ml and to kg=0.1 or 0.100 kg for correct sig figs)

I took 50.51 g Ice divided by/ 18.0148 g Ice (molar mass of ICE) = 2.804 mol Ice
m=mol/kg... so, 2.804 mol Ice divided by/ 0.100 kg= 28.0 m of salt water solution.
Is this correct?

2. Calculate the expected boiling point of Your salt water solution based on your mass of NaCl(9.059 gNaCl)
Boiling point formula: Δ T bp = mKbp ...

I'm confused about what to put where. Please help. Greatly appreciated!
Also, for my graph
For part 1: Heating Curve of Water ..
Times:0-16.00 min ...Temperatures in order, (8°C, °8C, 5, 4, 18, 34, 58, 76, 91, 97, 97, 98, 99, 99, 100, 100°C)
For part 2: Heating curve of Salt water solution
Times: 0-16:00 min... Temperatures in order, (1°C, 0°C, 0°C, 0°C, 0°C, 5.1°C, 34.3, 53.1, 71.1, 86.2, 97.2, 99.1, 99.1, 99.8, 100.1, 100.1°C, and 99.9°C)
My question is: The graph box is 39 by 39. My scale for time (x-axis) is by 1's and ends at 19 (38th box) and my temperature (y-axis) I'm not sure what my scale should be. I want to try to use as much as the 39 by 39 if it's possible.

Answer 1

I'm sorry but I don't see the problem. I tried to decipher the problem from your work but I don't know where you started. It would help if you posted the original problem, then showed what you did.