Question
what mass of formic acid must be dissolved in 250 ml of deionized water to produce a solution of pH 1.83?[ka of HCOOH=1.77*10^-4, Mw=46]
Answers
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[H3O+] = 10^-2.85 = 0.00141 M = [C6H5COO-]
6.3 x 10^-5 = (0.00141)^2 / x
x = 0.032 M
Moles = 0.032 x 0.350 L = 0.011
Mass = 0.011 mol x 122 g/mol = 1.34 g
6.3 x 10^-5 = (0.00141)^2 / x
x = 0.032 M
Moles = 0.032 x 0.350 L = 0.011
Mass = 0.011 mol x 122 g/mol = 1.34 g