Asked by Kaylee
40.0 mL of 0.1880 M formic acid is titrated with 30.0 mL of 0.2010 M NaOH. Pka of formic acid is 3.8. What is the pH of the titration?
Answers
Answered by
DrBob222
moles formic acid = M x L = ??
moles NaOH = M x L = ??
pH = pKa + log [(formate)/(formic acid)]
moles NaOH = M x L = ??
pH = pKa + log [(formate)/(formic acid)]
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