Question

40.0 mL of 0.1880 M formic acid is titrated with 30.0 mL of 0.2010 M NaOH. Pka of formic acid is 3.8. What is the pH of the titration?

Answer 1

moles formic acid = M x L = ??
moles NaOH = M x L = ??
pH = pKa + log [(formate)/(formic acid)]