Question

Responding to an alarm, a 100 kg, a fireman slides down a pole to the ground floor, 3.1 m below. The fireman starts at rest and lands with a speed of 3.8 m/s.

Find the average force exerted on the fireman by the pole.
Find the average force exerted on the fireman when the landing speed is 1.9 m/s.

Answer 1

Ok, first of all, this is the force of gravity acting against fricion

Net force= ma
mg-friction=ma
Now, you can find a

a=(Vf-Vi)/t where t is timedown. But t= height/avgvelocity = 2*height/Vf
now that you have a,
then find friction force

for each speed.