Question
Solid magnesium metal reacts with chlorine gas according to the following equation:
Mg + Cl2 --> MgCl2
What mass of magnesium chloride is formed in the reaction between 7 g of Mg and 13.2 g of Cl2
I got 7/24.3= .288
13.2/70.90= 1.861777
thats as far as i got and im stuck and don't know what to do next
Mg + Cl2 --> MgCl2
What mass of magnesium chloride is formed in the reaction between 7 g of Mg and 13.2 g of Cl2
I got 7/24.3= .288
13.2/70.90= 1.861777
thats as far as i got and im stuck and don't know what to do next
Answers
bobpursley
YOu got moles of Mg, and moles of Cl2. The reaction then will be limited by the moles of Mg.
So you will get .288moles of MgCl2
massMgCl2=.288*molmassMgCl2
So you will get .288moles of MgCl2
massMgCl2=.288*molmassMgCl2
The equation is limited by the element you have the least moles of.
In this case it will be the Cl2. 13.2/70.9 = .1862 mol
massMgCl2 = .1862 mol * molmassMgCl2
In this case it will be the Cl2. 13.2/70.9 = .1862 mol
massMgCl2 = .1862 mol * molmassMgCl2