Asked by sarah
Solid magnesium metal reacts with chlorine gas according to the following equation:
Mg + Cl2 --> MgCl2
What mass of magnesium chloride is formed in the reaction between 7 g of Mg and 13.2 g of Cl2
Answers
Answered by
DrBob222
You know this is a limiting reagent problem because it gives BOTH reactants.
Convert 7 g Mg to moles. moles = grams/molar mass.
Convert 13.2 g Cl2 to moles.
Using the coefficients in the balanced equation, convert moles Mg to moles MgCl2.
Same process, convert moles Cl2 to moles MgCl2.
The moles MgCl2 from the two processes will not be the same and one of them must be wrong. The correct value in limiting reagent problems is ALWAYS the smaller one and the material providing that number is the limiting reagent.
Using the smaller value, convert to grams. g = moles x molar mass.
Convert 7 g Mg to moles. moles = grams/molar mass.
Convert 13.2 g Cl2 to moles.
Using the coefficients in the balanced equation, convert moles Mg to moles MgCl2.
Same process, convert moles Cl2 to moles MgCl2.
The moles MgCl2 from the two processes will not be the same and one of them must be wrong. The correct value in limiting reagent problems is ALWAYS the smaller one and the material providing that number is the limiting reagent.
Using the smaller value, convert to grams. g = moles x molar mass.
Answered by
Anonymous
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